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-7x^2+15x+29=0
a = -7; b = 15; c = +29;
Δ = b2-4ac
Δ = 152-4·(-7)·29
Δ = 1037
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{1037}}{2*-7}=\frac{-15-\sqrt{1037}}{-14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{1037}}{2*-7}=\frac{-15+\sqrt{1037}}{-14} $
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